0=12x^2+x-20

Solution for 0=12x^2+x-20 equation:

0=12x^2+x-20

We move all terms to the left:

0-(12x^2+x-20)=0

We add all the numbers together, and all the variables

-(12x^2+x-20)=0

We get rid of parentheses

-12x^2-x+20=0

We add all the numbers together, and all the variables

-12x^2-1x+20=0

a = -12; b = -1; c = +20;
Δ = b2-4ac
Δ = -12-4·(-12)·20
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-31}{2*-12}=\frac{-30}{-24}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+31}{2*-12}=\frac{32}{-24}
=-1+1/3
$